The following figure shows the displacement versus time graph for two particle s A and B executing simple harmonic motions. The ratio of their maximum velocities is
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a
3:1
b
1:3
c
1:9
d
9:1
answer is A.
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Detailed Solution
For A, time period TA = 16 s (distance between two adjacent crests)For B, time period TB=2(20−8)=24s (length between the crest and trough shown =20s−8s=12s ) Also, amplitudes aA=10cm,aB=5cm Now, VmaxAVminB=ωAaAωBaB=2πTAaA2πTBaB=TBaATAaB=24×1016×5=31