Questions
The following figure shows the displacement versus time graph for two particle s A and B executing simple harmonic motions. The ratio of their maximum velocities is
detailed solution
Correct option is A
For A, time period TA = 16 s (distance between two adjacent crests)For B, time period TB=2(20−8)=24s (length between the crest and trough shown =20s−8s=12s ) Also, amplitudes aA=10cm,aB=5cm Now, VmaxAVminB=ωAaAωBaB=2πTAaA2πTBaB=TBaATAaB=24×1016×5=31Talk to our academic expert!
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The acceleration a of a particle undergoing S.H.M. is shown in the figure. Which of the labelled points corresponds to the particle being at – xmax
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