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Q.

In the following four Periods,(i) Time of revolution of a satellite just above the earth's surface Tst(ii) Period of oscillation of mass inside the tunnel bored along the diameter of the earth Tma(iii) Period of simple pendulum having a length equal to the earth's radius in a uniform field of 9.8 N/kg Tsp(iv) Period of an infinite length simple pendulum in the earth's real gravitational field Tis

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a

Tst>Tma

b

Tma>Tst

c

Tsp

d

Tst=Tma=Tsp=Tis

answer is C.

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Detailed Solution

(i) Tst=2π(R+h)3GM=2πRg [As h<
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