In the following four situations charged particles are at equal distance from the origin. Arrange them as per the magnitude of the net electric field at origin greatest first
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a
(i) > (ii) > (iii) > (iv)
b
(ii) > (i) > (iii) > (iv)
c
(i) > (iii) > (ii) > (iv)
d
(iv) > (iii) > (ii) > (i)
answer is C.
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Detailed Solution
If electric field due to charge |q| at origin is E then electric field due to charges |2q|,|3q|,|4q| and |5q| are respectively 2E,3E, 4E and 5EE(i)=(5E)2+(5E)2=52EE(ii)=(3E)2+(3E)2=32EE(iii)=4E+2E=6E and E(iv)=3E+E=4E⇒ E(i)>E(iii)>E(ii)>E(iv)