Q.
In the following P-V diagram, two adiabatics cut two isothermals at temperatures T1 and T2 (figure). The value of Va/Vd will be
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a
VbVc
b
VcVb
c
VdVa
d
VbVc
answer is A.
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Detailed Solution
For adiabatic process T1Vbγ−1= Constant For bc curve, T1Vbγ−1=T2Vcγ−1 or T2T1=VbVcγ−1 ……..(i)For ad curve, T1Vaγ−1=T2Vdγ−1 or T2T1=VaVdγ−1 ………(ii)From equation (i) and (ii), VbVc=VaVd.
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