First slide

Work done by Diff type of forces

Question

The force acting on an object varies with the distance travelled by the object as shown in Figure . Work done by the force in moving the object from x = 2 m to x=4 m is:

Easy

A

4 J
B

6 J
C

8 J
D

2J

Solution

work done = shaded area $= 2 \times \frac{4}{3} + \frac{1}{2} (4 / 3) (2)$
= 8/3 + 4/3
= 12 /3 = 4J

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