Q.

The force acting on an object varies with the distance travelled by the object as shown in Figure . Work done by the force in moving the object from x = 2 m to x=4 m is:

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a

4 J

b

6 J

c

8 J

d

2J

answer is A.

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Detailed Solution

work done = shaded area =2×43+12(4/3)(2)= 8/3 + 4/3= 12 /3 = 4J
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