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Q.

Force acting on a particle is given by F→=a→×P→, where ,a→   is a constant vector and  P→ is linear momentum of the particle. Choose the correct option(s):

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a

speed of the particle remain same

b

If  |F→| is constant and  a→⊥P→  path described by the particle is a circle

c

Linear momentum of the particle is conserved

d

Kinetic energy of the particle is conserved

answer is A.

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Detailed Solution

F→=a→×P→F→  is always perpendicular to   P→So , It can’t change speed hence KE is also constant.P→ will change its direction. |F→| will be constant; so particle will move on a circular trajectory.
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