Force acting on a particle is given by F→=a→×P→, where ,a→ is a constant vector and P→ is linear momentum of the particle. Choose the correct option(s):
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a
speed of the particle remain same
b
If |F→| is constant and a→⊥P→ path described by the particle is a circle
c
Linear momentum of the particle is conserved
d
Kinetic energy of the particle is conserved
answer is A.
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Detailed Solution
F→=a→×P→F→ is always perpendicular to P→So , It can’t change speed hence KE is also constant.P→ will change its direction. |F→| will be constant; so particle will move on a circular trajectory.