First slide

Work done by Diff type of forces

Question

Force acting on a particle moving in a straight line varies with the velocity of the particle as F = K/v, where K is a constant. The work done by this force in time t is

Moderate

A

$\frac{K}{v^{2}} t$
B

$2 K t$
C

$K t$
D

$\frac{2 K t}{v^{2}}$

Solution

$F v = K m \frac{d v}{d t} v = K m d v v = K d t o n i n t r e g a t i o n m \frac{v^{2}}{2} = K t \frac{1}{2} m v^{2} = c h a n g e i n k i n e t i c e n e r g y = w o r k d o n e$

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