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Q.

A force acting on a particle moving in the xy-plane is given by F=2yi^+x2j^N, where x and y are in m. The particle moves along a straight line from the origin to (5, 5). The work done by F is:

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a

125 J

b

66.7 J

c

35 J

d

25 J

answer is B.

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Detailed Solution

y=mx+c . Here m=1 and c = 0 . Work done W = ∫ F→.dr→and dr→=dx i^ +dyj ^w=∫05 2×dx+∫05 y2dyy=x.

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A force acting on a particle moving in the xy-plane is given by F=2yi^+x2j^N, where x and y are in m. The particle moves along a straight line from the origin to (5, 5). The work done by F is: