A force acting on a particle moving in the xy-plane is given by F=2yi^+x2j^N, where x and y are in m. The particle moves along a straight line from the origin to (5, 5). The work done by F is:

see full answer

21% of IItians & 23% of AIIMS delhi doctors are from Sri Chaitanya institute !!

An Intiative by Sri Chaitanya

125 J

66.7 J

35 J

25 J

answer is B.

(Unlock A.I Detailed Solution for FREE)

Ready to Test Your Skills?

Check your Performance Today with our Free Mock Test used by Toppers!

Take Free Test

Detailed Solution

y=mx+c . Here m=1 and c = 0 . Work done W = ∫ F→.dr→and dr→=dx i^ +dyj ^w=∫05 2×dx+∫05 y2dyy=x.

Watch 3-min video & get full concept clarity