First slide

Work

Question

Force acting on a particle varies with displacement as shown in figure. The work done from x=-4m to x=+4m is

Moderate

A

-6J
B

6J
C

-18J
D

18J

Solution

Work done=
W= Area of F-x graph
W = Area of $Δ BCD+Area of Δ OAB+Area of Δ OAEF+Area of Δ EFG$
W= $[\frac{1}{2} \times 2 \times - 6] + [\frac{1}{2} \times 2 \times 6] + [2 \times 6] + [\frac{1}{2} \times 2 \times 6]$
W=12+6=18J

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