Questions
Force acting upon a charged particle kept between the plates of a charged condenser is F. If one plate of the condenser is removed, then the force acting on the same particle will become
a
0
b
F / 2
c
F
d
2F
detailed solution
Correct option is B
Initially F = qE and E=σε0 ∴F=qσε0If one plate is removed, then E becomes σ2ε0So F'=qσ2ε0=F2Talk to our academic expert!
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