Capacitance
Question
Force acting upon a charged particle kept between the plates of a charged capacitor is E If one of the plates of the capacitor is removed, force acting on the same particle will become
Easy
Solution
The electric field between the oppositely charged plates of a capacitor is twice that due to one plate. Hence when one plate is removed, the electric field becomes half and thereby the force reduces to half i.e., F/2.
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