First slide

Power

Question

A force applied by an engine of a train of mass $2 .05 \times 10^{6} kg$ changes its velocity from 5 m/s to 25 m/s in 5 minutes. The power of the engine is

Moderate

A

1.025 MW
B

2.05 MW
C

5 MW
D

6 MW

Solution

Power $= \frac{Work done}{time} = \frac{\frac{1}{2} m (v^{2} - u^{2})}{t}$
$P = \frac{1}{2} \times \frac{2 .05 \times 10^{6} \times [{(25)}^{2} - (5^{2})]}{5 \times 60}$
$P = 2 .05 \times 10^{6} W = 2 .05 MW$

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