The force between the plates of a parallel plate capacitor of capacitance C and distance of separation of the plates d with a potential difference V between the plates, is
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a
CV22d
b
C2V22d2
c
C2V2d2
d
V2dC
answer is A.
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Detailed Solution
Force between the plates of a capacitor is = field due to one plate ×charge on the other =σ2ε0Q=Q22ε0A=C2V22ε0Add=CV22d