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Q.

The force between the plates of a parallel plate capacitor of capacitance C and distance of separation of the plates d with a potential difference V between the plates, is

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a

CV22d

b

C2V22d2

c

C2V2d2

d

V2dC

answer is A.

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Detailed Solution

Force between the plates of a capacitor is  = field due to one plate ×charge on the other =σ2ε0Q=Q22ε0A=C2V22ε0Add=CV22d
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