First slide

Magnetism

Question

Force between two identical bar magnets whose centers are ‘ r’ meter apart is 4.8 N
When their axis are in the same line. If the separation is increased to ‘2r’ meter, then the force between them reduced and becomes ‘P’ . Then P is_____N.

Moderate

Solution

Two bar magnets placed along same axis line at distance ‘ r’ (between their centres) exerts a force on each other is ‘F’.
$F \propto \frac{M_{1} M_{2}}{r^{4}}$
$\Rightarrow \frac{F_{1}}{F_{2}} = {(\frac{r_{2}}{r_{1}})}^{4}$
$\Rightarrow F_{2} = {(\frac{r_{1}}{r_{2}})}^{4} . F_{1}$
$\Rightarrow F_{2} = \frac{1}{16} . (4.8) = 0.3 N$

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