First slide

The bar magnet

Question

Force between two identical bar magnets whose centres are r metre apart is 4.8 N, when their axes are in the same line. If separation is increased to 2r, the force between them is reduced to

Moderate

A

2.4 N
B

0.6 N
C

1.2 N
D

0.3 N

Solution

$\frac{F^{1}}{F} \Rightarrow {(\frac{r}{r_{1}})}^{4}; \frac{4.8}{F^{1}} = {(\frac{2 r}{r})}^{4}, F^{1} = 0.3 N$

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