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Q.

The force on a body executing SHM is 2 N when the displacement is 2 cms if the amplitude of oscillations is 5 cm. What is the total energy associated with the SHM?

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a

1.25×10−2J

b

125×10−2J

c

12.5×10−2J

d

0.125×10−2J

answer is C.

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Detailed Solution

Total EnergyTE of oscillator is               TE=12mω2A2,                k=mω2                F=kx=mω2x           mω2=F/x substitute in TE,             TE=12FxA2 Substitute the given values            TE=1222×10−2×5×10−22           TE=12×110−2×25×10−4           TE=1250×10-4          TE=0.125 or 12.5×10−2J
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