First slide

Work done by Diff type of forces

Question

The force constant of a weightless spring is 16 N/m. A body of mass 2.0 kg suspended from it is pulled down
through 5 cm and then released. The maximum kinetic energy of the system (spring + body) will be

Easy

A

$2 \times 10^{- 2} J$
B

$4 \times 10^{- 2} J$
C

$8 \times 10^{- 2} J$
D

$16 \times 10^{- 2} J$

Solution

$Maximum K.E. = \frac{1}{2} k x^{2} ∴ (K . E .)_{max} = \frac{1}{2} \times (16) \times {(5 \times 10^{- 2})}^{2} = 2 \times 10^{- 2} J$

Get Instant Solutions

When in doubt download our app. Now available Google Play Store- Doubts App

Recieve an sms with download link

Doubts App

OR

SCAN ME

Doubts App

Doubts App