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The force constant of a weightless spring is 16 N/m. A body of mass 2.0 kg suspended from it is pulled down
through 5 cm and then released. The maximum kinetic energy of the system (spring + body) will be

a
2×10−2J
b
4×10−2J
c
8×10−2J
d
16×10−2J

detailed solution

Correct option is A

Maximum K.E. =12kx2 ∴ (K.E.)max=12×(16)×5×10−22 =2×10−2J

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Similar Questions

Two similar springs P and Q have spring constants Kp and KQ such that Kp > KQ. They are stretched first by the same amount (case a), then by the same force (case b). The work done by the springs WP and WQ are related as, in case (a) and case (b), respectively.


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