The force constant of a weightless spring is 16 N/m. A body of mass 1.0 kg suspended from it is pulled down through 5 cm and then released. The maximum kinetic energy of the system (spring + body) will be

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2×10−2 J

4×10−2 J

8×10−2 J

16×10−2 J

answer is A.

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Detailed Solution

Max. K.E. of the system = Max. P.E. of the system12kx2=12×(16)×(5×10−2)2=2×10−2 J

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