First slide

Work

Question

The force constant of a wire is k and that of another wire is 2k When both the wires are stretched through same distance, then the work done

Moderate

A

$W_{2} = 2 W_{1}^{2}$
B

$W_{2} = 2 W_{1}$
C

$W_{2} = W_{1}$
D

$W_{2} = 0 .5 W_{1}$

Solution

$W = \frac{1}{2} {kx}^{2}$
If both wires are stretched through same distance then $W \propto k$ . As $k_{2} = 2 k_{1}$ so $W_{2} = 2 W_{1}$

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