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The force constants of two springs are and . Both are stretched till their elastic energies are equal. If the stretching forces are and , then is
detailed solution
Correct option is C
Given elastic energies are equal i.e., 12k1x12=12k2x22⇒k1k2=x2x12 and using F=kx⇒F1F2=k1x1k2x2=k1k2×k2k1=k1k2Talk to our academic expert!
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An ideal spring with spring-constant K is hung from the ceiling and a block of mass M is attached to its lower end. The mass is released with the spring initially unstretched. Then the maximum extension in the spring is
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