Q.

The force exerted by the floor of an elevator on the foot of a person standing there, is more than his weight , if the elevator is

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a

Going down and slowing down

b

Going up and speeding up

c

Going up and slowing down

d

both a and b

answer is D.

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Detailed Solution

When elevator goes up, then equation of motion is R−mg−ma⇒R=m(g+a)  i.e., apparent weight > real weight.When elevator goes down and slowing down means retarding a is replaed by -a, then equation of motion is mg−R=m-a⇒R=m(g+a)  i.e., apparent weight > real weight.
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The force exerted by the floor of an elevator on the foot of a person standing there, is more than his weight , if the elevator is