Questions
The force F acting on a body moving along x-axis varies with the position x of the particle as shown in the graph. The body is in stable equilibrium at
a
x=x1
b
x=x2
c
both x1 and x2
d
neither x1 nor x2
detailed solution
Correct option is B
If d2Udx2>0, then it is the position of stable equillibriumIf d2Udx2<0, then it is the position of unstable equillibriumAt x1, dFdx>0⇒ddx−dUdx>0, i.e., d2Udx2<0x1 is the position of unstable equillibriumAt x2, dFdx<0⇒ddx−dUdx<0, i.e., d2Udx2>0x2 is the position of stable equillibriumTalk to our academic expert!
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The value of for which two vectors are perpendicular to. each other is
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