First slide

Work done by Diff type of forces

Question

A force F acting on an object varies with distance x as shown here. The force is in N and x is in m. The work done by the force in moving the object from x = 0 to x = 6m is :

Easy

A

13.5 J
B

12.75 J
C

4.5 J
D

9.0 J

Solution

Work done = Area of F -x graph
$= 3 \times 2 .5 + \frac{1}{2} \times (3 .5) (3) = 7 .5 + 5 .25 = 12 .75 J$

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