The force F acting on a particle of mass m is indicated by the force-time graph shown below. The change in momentum of the particle over the time interval from zero to 8 s is

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24 Ns

20 Ns

12 Ns

6 Ns

answer is C.

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Detailed Solution

F = dpdt ⇒ dp = F.dt or ∫pipfdp = ∫F.dtChange in momentum = Area under the F versus t graph in the interval= (12×2×6)-(2×3)+(4×3)= 6-6+12 = 12 NS

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