Questions
A force F = bt (where b is a constant) is applied at an angle to a mass m kept on a smooth horizontal plane. The velocity of mass m at the moment of its breaking off the plane is
detailed solution
Correct option is A
btcosα=mdvdt ......(i)N+btsinα=mg ........(ii)For breaking off N=0 Therefore from (ii), t=mgbsinα=t0 (say) From (i), m∫0v dv=(bcosα)∫0t0 tdtmv=(bcosα)t022=(bcosα)2m2g2b2sin2αv=mg2cosα2bsin2αTalk to our academic expert!
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A block of mass kg rests on a horizontal frictionless xy-plane. What would be the acceleration of the block if it is subjected to two forces as shown in figure?
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