Force F and density d are related as F = αβ+d then the dimensions of α and β are
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a
M32L−12T-2, M12L−32 respectively
b
M32L12T−2, M−12L32 respectively
c
M32L−12T2, M−12L32 respectively
d
M32L12T−2, M12L32 respecitvely
answer is A.
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Detailed Solution
The dimensions of left hand side expression should be same as right hand side expression.αβ+d = F =MLT−2The dimensional formula for β should be same as the dimensional formula for dβ = d = ML−312 = M12L−32Hence [α] = βF = M12L−32MLT−2⇒ α = M32L−12T-2