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Q.

A force (F→)=3i^+cj^+2k^  acting on a particle causes a displacement: (s→) =−4i^+2j^+3k^  in its own direction. If the work done is 6 J, then the value of ‘c’ is

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a

0

b

1

c

6

d

12

answer is C.

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Detailed Solution

W=(3i^+cj^+2k^).(−4i^+2j^+3k^)=6 JW=−12+2c+6=6  ⇒c=6
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