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A force of F→=2i^+3j^ acting on a body mass 2kg which was initially at rest. If the displacement produced by the force is 12i^ +8j^ .Then the final velocity of the body is

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answer is 3.

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Detailed Solution

work done F→.S→ =12mv2-0 = change in kinetic energy2i^+3j^.12i^+8j^ =48 J12mv2=48 , v=43

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