A force F¯ = (5i∧+3j∧+2k∧) N is applied over a particle which displaces it from its origin to the point r¯ = (2i∧−j∧) m . The work done on the particle in Joules is
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a
-7 J
b
+7 J
c
10 J
d
13 J
answer is B.
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Detailed Solution
we know that work done is W = F¯·r¯ =force . displacement W = (5i∧+3j∧+2k∧) (2i∧−j∧ ) W = 10−3 = 7 J