A force F →=6i^+2j^−3k^ acts on a particle and produces a displacement of s →=2i^−3j^+xk^. If the work done is zero, the value of x is
– 2
1/2
6
2
W=F→.s→=(6i^+2j^−3k^).(2i^−3j^+xk^)=0
12−6−3x=0 ⇒x=2