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Questions  

A force of F=2i+3j2k acts at a point (2, –3, 1). Then magnitude of torque about point (0,0,2) will be

a
6 units
b
3 5 units
c
65 units
d
8 units

detailed solution

Correct option is C

Here  r→ = 2−0i+j−3−0+k1−2=2i −3j−kτ¯ = r¯ ×F¯  =ijk2−3−123−1= 6i+12k = 65

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