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A force F→=(4i→−3j→+7k→)N moves a particle from (i^+j^+k^)m to 2i^+3j^−5k^ m. The work done by the force is

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a

44J

b

-44J

c

8J

d

-36J

answer is B.

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Detailed Solution

W=F→⋅Δr→=[4i^−3j^+7k^]⋅[(2i^+3j^−5k^)−(i^+j^+k^)]W=(4i^−3j^+7k^)⋅(i^+2j^−6k^)W=4−6−42=−44J

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A force F→=(4i→−3j→+7k→)N moves a particle from (i^+j^+k^)m to 2i^+3j^−5k^ m. The work done by the force is