A force F= 2i +3j- 4kN acts on a particle which is constrained to move in the XOY plane along the line x = y. If the particle moves 52m, the work done by force in joule is
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a
252
b
558
c
25
d
10
answer is C.
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Detailed Solution
F = 2 i + 3 j - 4 k as x=y s=52 then s = 5 i + 5 j work done = 2x5 + 3x 5 = 25 joule