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Q.

A force   F= 2i +3j- 4kN acts on a particle  which is constrained to move in the XOY plane along the line x = y. If the particle moves 52m, the work done by force in joule is

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a

252

b

558

c

25

d

10

answer is C.

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Detailed Solution

F = 2 i + 3 j - 4 k        as  x=y    s=52       then  s = 5 i + 5 j work done = 2x5 + 3x 5 = 25 joule
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