A force F→=(5i^+6j^)N is acting at point A(2m,4m). Then the moment of the force about the point B(1m, 1m) in N-m is
7j^
(8i^−6j^)
−9k^
−6k^
rAB⇀=Position vector of A relative to B
=(2−1)i^+(4−1)j^ m=(i^+3j^)m
∴ M→B=r→AB×F→=|i^j^k^130560|N−m=−9 k^ N−m