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Q.

A force F = ( 6i −8 j ) N, acts on a particle and  displaces it over 4 m along the X-axis and then displaces it over 6 m along the Y-axis. The total work done during the two displacements is

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a

72 J

b

24 J

c

–24 J

d

zero

answer is C.

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Detailed Solution

Given s = 4 i + 6 j N   and  F = 6 i - 8 j work done   W = F . S =  6×4 -8 ×6 = -24   J
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