A force F = ( 6i −8 j ) N, acts on a particle and displaces it over 4 m along the X-axis and then displaces it over 6 m along the Y-axis. The total work done during the two displacements is

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72 J

24 J

–24 J

zero

answer is C.

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Detailed Solution

Given s = 4 i + 6 j N and F = 6 i - 8 j work done W = F . S = 6×4 -8 ×6 = -24 J

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