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Q.

A force F→=(3i^+4j^) Newton acts on a particle moving along a line 4y + kx = 3. The work done by the force is zero if the value of k is

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a

1

b

2

c

3

d

4

answer is C.

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Detailed Solution

4y+kx=34y=3−kxy=−k4x+34 slope m1=k4F⇒3i^+4j^ slope m2⇒43 for perpendicular m1×m2=−1−k4×43=−1k=3
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