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Q.

A force F=(5i^+3j^) newton is applied over a particle which displaces it from its origin to the point r=(2i^−1j^) metres. The work done on the particle is

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a

– 7 joules

b

+ 13 joules

c

+ 7 joules

d

+ 11 joules

answer is C.

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Detailed Solution

W=F→.s→=(5i^+3j^).(2i^−j^)=10−3=7J

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