A force F=(5i^+3j^) newton is applied over a particle which displaces it from its origin to the point r=(2i^−1j^) metres. The work done on the particle is
– 7 joules
+ 13 joules
+ 7 joules
+ 11 joules
W=F→.s→=(5i^+3j^).(2i^−j^)=10−3=7J