Questions
A force F =(2i+2k) dyne displaces a particle by an amount = (2 i + 2j) cm in 16 sec. The power developed by the force F is
detailed solution
Correct option is D
Power = work done/time taken.Further, work done W= F . S∴W=(2i+2k)⋅(2i+2j) dyne-cm =4 ergNow P=4 erg16sec=0⋅25erg/secTalk to our academic expert!
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