First slide

Power

Question

A force F =(2i+2k) dyne displaces a particle by an amount $\vec{d}$ = (2 i + 2j) cm in 16 sec. The power developed by the force F is

Moderate

A

0.5 erg/sec
B

0.5 watt
C

0.25 watt
D

0.25 erg/sec

Solution

Power = work done/time taken.
Further, work done W= F . S
$\begin{array}{l} ∴ W = (2 i + 2 k) \cdot (2 i + 2 j) dyne - cm \\ = 4 erg \\ Now P = \frac{4 erg}{16 \sec} = 0 \cdot 25 erg / \sec \end{array}$

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