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Q.

A force of −Fk^ acts on origin, then the torque about the point (1,−1) is :

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a

F(i^−j^)

b

-F(i^−j^)

c

−F(i^+j^)

d

F(j^−i^)

answer is D.

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Detailed Solution

τ→=r→×F→ Force acts on origin so r→ is position vector of origin wrt. (1,−1) sor→=−i^+j^,F→=−Fk^τ→=(−i^+j^)×(−Fk^)=−Fi^+Fj^
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