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Q.

A force of F = 0.5 N is applied on lower block as shown in figure . The work done by lower block on upper block for a displacement of 3 m of the upper block with respect to ground is (Take, 9 = 10ms 2)

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a

-0.5 J

b

0.5 J

c

2 J

d

-2J

answer is B.

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Detailed Solution

Maximum acceleration of I kg block,   amax=μg=1 ms-2Common acceleration without relative motion between two blocks,, a=0.53 ms-2Since,  a
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