First slide

Work done by Diff type of forces

Question

Force F on a particle moving in a straight line varies with distance d as shown in the figure. The work done on the particle during its displacement of 12 m is

Easy

A

21 J
B

26 J
C

13 J
D

18 J

Solution

Work done = Area under (,F - x) graph
= 2 $\times (7 - 3) + \frac{1}{2} \times 2 \times (12 - 7)$
= $8 + \frac{1}{2} \times 10 = 8 + 6 = 13 J$

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