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Q.

A force  F→=2ti+5t2j^N acts on a body due to which displacement varies as S→=3t2i^+4k^m   work done in 3 seconds is

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a

142J

b

322J

c

108J

d

38J

answer is C.

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Detailed Solution

S→=3t2i^+4k^⇒ds→=6tdti^W=∫F¯⋅ds→=∫2t^+5t2j^⋅(6tdti^)W=12∫03 t2dt=12×t3303=4×27W=108J
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