Questions
A force of is acting on a particle on a particle of mass 1Kg at rest, where F is in newton and t is in seconds. Work done by this force in first 1 second is
detailed solution
Correct option is A
F = 10t+3t2 mdvdt= 10t+3t2 dv= (10t+3t2)dtv= 10t22+t30 1v after 1 sec 6 m/s. work done is equal to change in K.E= 12(1)(6)2= 18 JTalk to our academic expert!
Similar Questions
A body of mass 3 kg is under a force which causes a displacement in it, given by s =t2 / 3 (in m). Find the work done by the force in 2 second
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