First slide
Periodic Motion
Question

A force F1 when it acts on a body causes it to execute SHM of time period T1 whereas another force F2 when actions on the same body causes it to execute SHM of time period T2.If both forces act on the body simultaneously and in a manner that they are always acting in the same phase, the time period of SHM will be:

Easy
Solution

As
 T1kand keff=k1+k2 So,            1T2=1T12+1T22            T=T1T2T12+T22

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