A force F=−4x+8 (inN) is acting on block where x is the position of block in metres. The energy of oscillation is 32 J. The block oscillates between two points, out of which value of position of one point (in m) is an integer from 0 to 9. The value of x is _______.
see full answer
Your Exam Success, Personally Taken Care Of
1:1 expert mentors customize learning to your strength and weaknesses – so you score higher in school , IIT JEE and NEET entrance exams.
An Intiative by Sri Chaitanya
answer is 6.
(Unlock A.I Detailed Solution for FREE)
Best Courses for You
JEE
NEET
Foundation JEE
Foundation NEET
CBSE
Detailed Solution
F=−4x+8=−4(x−2)=−4x0It is equation of SHM.Mean position is x = 2 m, (as F = 0)From F=-4x0, K = 4N/mA=2EK1/2=(2)(32)41/2=4mThe mean position is x = 2 mso, extreme positions of the points are 6 m and - 2 m. The answer is 6 m.