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Question

A force F = (3x + 4) newton displaces an object of mass 10 kg from x = 0 to x = 4m. If the speed of the object at x = 0 is 2ms-1, its speed at x = 4m will be ___m/s

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Solution

Work done by the force is

dW=fdxW=04(3x+4)dx    =3x22+4x04=40J

From work energy principle, work done = change in kinetic energy.

    W=Δk=12mv2u2    40=12×10×v222v=23=3.46ms1


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