A force of  F=(2xy−3z) j^−8zk^ is applied on a particle. The work done by the force in displacing the particle from (0,0,0) to (2,4,0) as shown in figure is _______

y=2x2dy=4xdxW=∫F→⋅dr→=∫[(2xy−3z)j^−8zk^]⋅(dxi^+dyj^+dzk^)W=∫2x⋅2x2dy−∫04 3zdy−∫00 8zdzW=4∫02 x3×4xdx−3z∫(2,4,0)(0,0,0)dy−8z200W=16∫02 x4dx−0−0W=16x5502=16×325=5125=102.5J