A force F→=(3xy−5z)j^+4zk^ is applied on a particle. The work done by the force when the particle moves from point (0, 0, 0) to point (2, 4, 0) as shown in figure is
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a
2805 units
b
1405 units
c
2325 units
d
1925 units
answer is D.
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Detailed Solution
The z-component of the force and the x-component of displacement are ineffective here.dW=Fydy=3xy⋅dy(∵z=0)=6x4dx ∵y=x2Integrating between x = 0 and x = 2 gives the result.