Q.
A force F=20+10 y acts on a particle in y -direction where F is in newton and y in meter. Work done by this force to move the particle from y=0 to y=1 m is
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a
20 J
b
30 J
c
5 J
d
25 J
answer is D.
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Detailed Solution
Given :F=20+10y work done, W=∫F·dy =∫01(20+10y)dy=20y+102y201=20+102=25 J
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