Q.

A force F=20+10 y acts on a particle in y -direction where F is in newton and y in meter. Work done by this force to move the particle from y=0 to y=1 m is

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a

20 J

b

30 J

c

5 J

d

25 J

answer is D.

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Detailed Solution

Given :F=20+10y  work done, W=∫F·dy =∫01(20+10y)dy=20y+102y201=20+102=25 J
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A force F=20+10 y acts on a particle in y -direction where F is in newton and y in meter. Work done by this force to move the particle from y=0 to y=1 m is