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Work done by Diff type of forces

A force F=20+10 y acts on a particle in y -direction where F is in newton and y in meter. Work done by this force to move the particle from y=0 to y=1 m is


 Given :F=20+10y  work done, W=F·dy =01(20+10y)dy=20y+102y201=20+102=25 J

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