Questions
A force of 10i - 3j + 6 k newton acts on a body of 5kg and it displaces from 6i+5j-3k metre to 10 i -2j+7k metre. The work done is
a
100 j
b
0
c
121 j
d
None
detailed solution
Correct option is C
W=F⋅ds=(10i−3j+6k)⋅[(10i−2j+7k)−(6i+5j−3k)]]=(10i−3j+6k)⋅(4i−7j+10k)=40+21+60=121JTalk to our academic expert!
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